350x-500x^2=0

Solution for 350x-500x^2=0 equation:

350x-500x^2=0

a = -500; b = 350; c = 0;
Δ = b2-4ac
Δ = 3502-4·(-500)·0
Δ = 122500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{122500}=350$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(350)-350}{2*-500}=\frac{-700}{-1000}
=7/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(350)+350}{2*-500}=\frac{0}{-1000}
=0
$